Thanks to all of you who support me on Patreon You da real mvps! Stepbystep explanation Compare the equation to that of an ellipse with center (h, k) and axes of lengths 2a and 2b We see that (h, k) = (4, 0) and a=2, b=3 This tells us the$1 per month helps!!
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Graph the circle (x-4)^2+(y+1)^2=9
Graph the circle (x-4)^2+(y+1)^2=9-Graph (x^2)/4 (y^2)/9=1 x2 4 y2 9 = 1 x 2 4 y 2 9 = 1 Simplify each term in the equation in order to set the right side equal to 1 1 The standard form of an ellipse or hyperbola requires the #(x4)^2(y1)^2=9# This tells us that we have a center at #(4,1)#, and a radius of #3# To think about graphing the radius, a radius of #3# is just the distance from the center of
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Detailed step by step solution for x^24xy^29x9=0 This website uses cookies to ensure you get the best experience By using this website, you agree to our Cookie Policy Learn more AcceptFind all points on the graph of y=\sin ^{2} x where the tangent line has slope 1 Watch the full video athttps//wwwnumeradecom/questions/findallpointsAlgebra Graph (x^2)/4 (y^2)/9=1 x2 4 − y2 9 = 1 x 2 4 y 2 9 = 1 Simplify each term in the equation in order to set the right side equal to 1 1 The standard form of an ellipse or hyperbola
Graphing the Hyperbola y^2 1 Answer 0 votes x 2/4 y 2 /9 = 1 The equation is y 2/9 x 2/4 = 1 The standard form of the equation of an ellipse center (h, k) with major and minor axes of lengths 2aGraph (x^2)/4(y^2)/9=1 Simplify each term in the equation in order to set the right side equal to The standard form of an ellipse or hyperbola requires the right side of the equation be
For the equation of each ellipse, find the coordinates of the center, foci, and vertices Then graph the equation x 2 4 y 2 9 = 1 \frac{x^{2}}{4}\frac{y^{2}}{9}=1 4 x 2 9 y 2 = 1Graph (x^2)/4(y^2)/9=1 Simplify each term in the equation in order to set the right side equal to The standard form of an ellipse or hyperbola requires the right side of the equation be This isAnswers archive Click here to see ALL problems on Quadraticrelationsandconicsections Question Find the foci of the graph of x^2/4 y^2/9 = 1 Graph the ellipse Answer by
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Incoming Term: x^2/4+y^2/9=1 graph, graph the circle (x-4)^2+(y+1)^2=9, graph the hyperbola with equation (x+3)^2/4-(y-3)^2/9=1,
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